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C program for finding the frequency of given word in a string:

#include<stdio.h>
int main(){
    int i=0,k=0,yes=0;
    char word[10],str[50];
    printf("Enter string:\t");
    gets(str);
    printf("Enter word\t");
    gets(word);
   while(str[i]!='\0')
   {
       if(word[k]==str[i])
       {
           i++;
           k++;
           if(k==(strlen(word)-1))
           {
               yes++;
               k=0;
           }
       }
       else
        i++;
   }
   printf("%s is repeating %d times",word,yes);
return 0;
}

How to print 

           1

       232

     34543

   4567654

 567898765

                                                    Here is the simplified source code which will generate the pattern for the entered value of row provided by the user. 

#include<stdio.h>
int main(){
int n,i,j,k,p;
printf("Enter no of row:\t");
scanf("%d",&n);
for(i=1;i<=n-1;i++)
{
    k=i;
    p=k;
    for(j=1;j<=2*n-1;j++)
    {
        if((j>=n+1-i) && (j<=n-1+i)){
            printf("%d",p);
            if(k<2*i-1){
                k++;
                p=k;
            }
            else{
                p--;
            }
           
        }
        else
            printf(" ");
    }
    printf("\n");
}
return 0;
}

output will look like: